adding the remaining of lecture 10

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Jidong Xiao
2023-10-02 10:32:48 -04:00
parent d25a7c7f7a
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@@ -161,12 +161,147 @@ cout << "1st value: " << ll->value << "\n"
} }
``` ```
## 10.5 Iterator Declarations and Operations ## 10.5 Definition: A Linked List
to be added soon. - The definition is recursive: A linked list is either:
- Empty, or
- Contains a node storing a value and a pointer to a linked list.
- The first node in the linked list is called the head node and the pointer to this node is called the head pointer.
The pointers value will be stored in a variable called head.
## 10.6 Leetcode Exercises ## 10.6 Visualizing Linked Lists
- The head pointer variable is drawn with its own box. It is an individual variable. It is important to have a
separate pointer to the first node, since the “first” node may change.
- The objects (nodes) that have been dynamically allocated and stored in the linked lists are shown as boxes,
with arrows drawn to represent pointers.
- Note that this is a conceptual view only. The memory locations could be anywhere, and the actual values
of the memory addresses arent usually meaningful.
- The last node MUST have NULL for its pointer value — you will have all sorts of trouble if you dont ensure this!
- You should make a habit of drawing pictures of linked lists to figure out how to do the operations.
## 10.7 Basic Mechanisms: Stepping Through the List
- Wed like to write a function to determine if a particular value, stored in x, is also in the list.
- We can access the entire contents of the list, one step at a time, by starting just from the head pointer.
We will need a separate, local pointer variable to point to nodes in the list as we access them.
We will need a loop to step through the linked list (using the pointer variable) and a check on each value
## 10.8 Exercise: Write is there
```cpp
template <class T> bool is_there(Node<T>* head, const T& x) {
}
```
- If the input linked list chain contains n elements, what is the order notation of is there?
## 10.9 Basic Mechanisms: Pushing on the Back
- Goal: place a new node at the end of the list.
- We must step to the end of the linked list, remembering the pointer to the last node.
- This is an O(n) operation and is a major drawback to the ordinary linked-list data structure we are
discussing now. We will correct this drawback by creating a slightly more complicated linking structure
in our next lecture.
- We must create a new node and attach it to the end.
- We must remember to update the head pointer variables value if the linked list is initially empty.
Hence, in writing the function, we must pass the pointer variable by reference.
## 10.10 Exercise: Write push_front
```cpp
template <class T> void push_front( Node<T>* & head, T const& value ) {
}
```
- If the input linked list chain contains n elements, what is the order notation of the implementation of push front?
## 10.11 Exercise: Write push_back
```cpp
template <class T> void push_back( Node<T>* & head, T const& value ) {
}
```
- If the input linked list chain contains n elements, what is the order notation of this implementation of
push back?
## 10.12 Inserting a Node into a Singly-Linked List
- With a singly-linked list, well need a pointer to the node before the spot where we wish to insert the new
item.
- If p is a pointer to this node, and x holds the value to be inserted, then the following code will do the insertion.
Draw a picture to illustrate what is happening.
```cpp
Node<T> * q = new Node<T>; // create a new node
q -> value = x; // store x in this node
q -> next = p -> next; // make its successor be the current successor of p
p -> next = q; // make p's successor be this new node
```
- Note: This code will not work if you want to insert x in a new node at the front of the linked list. Why not?
## 10.13 Removing a Node from a Singly-Linked List
- The remove operation itself requires a pointer to the node before the node to be removed.
- Suppose p points to a node that should be removed from a linked list, q points to the node before p, and head
points to the first node in the linked list. Note: Removing the first node is an important special case.
- Write code to remove p, making sure that if p points to the first node that head points to what was the second
node and now is the first after p is removed. Draw a picture of each scenario.
## 10.14 Exercise: Singly-Linked List Copy
Write a recursive function to copy all nodes in a linked list to form an new linked list of nodes with identical structure
and values. Heres the function prototype:
```cpp
template <class T> void CopyAll(Node<T>* old_head, Node<T>*& new_head) {
}
```
## 10.15 Exercise: Singly-Linked List Remove All
Write a recursive function to delete all nodes in a linked list. Heres the function prototype:
```cpp
template <class T> void RemoveAll(Node<T>*& head) {
}
```
<!-- ## 10.16 Leetcode Exercises
- [Leetcode problem 27: Remove Element](https://leetcode.com/problems/remove-element/). Solution: [p27_removeelement.cpp](../../leetcode/p27_removeelement.cpp) - [Leetcode problem 27: Remove Element](https://leetcode.com/problems/remove-element/). Solution: [p27_removeelement.cpp](../../leetcode/p27_removeelement.cpp)
- [Leetcode problem 58: Length of Last Word](https://leetcode.com/problems/length-of-last-word/). Solution: [p58_lengthoflastword.cpp](../../leetcode/p58_lengthoflastword.cpp) - [Leetcode problem 58: Length of Last Word](https://leetcode.com/problems/length-of-last-word/). Solution: [p58_lengthoflastword.cpp](../../leetcode/p58_lengthoflastword.cpp)
- [Leetcode problem 283: Move Zeroes](https://leetcode.com/problems/move-zeroes/). Solution: [p283_movezeroes.cpp](../../leetcode/p283_movezeroes.cpp) - [Leetcode problem 283: Move Zeroes](https://leetcode.com/problems/move-zeroes/). Solution: [p283_movezeroes.cpp](../../leetcode/p283_movezeroes.cpp)
-->