adding queue based level order traversal
This commit is contained in:
44
leetcode/p102_level_order_traversal.cpp
Normal file
44
leetcode/p102_level_order_traversal.cpp
Normal file
@@ -0,0 +1,44 @@
|
||||
/**
|
||||
* Definition for a binary tree node.
|
||||
* struct TreeNode {
|
||||
* int val;
|
||||
* TreeNode *left;
|
||||
* TreeNode *right;
|
||||
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
|
||||
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
|
||||
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
|
||||
* };
|
||||
*/
|
||||
class Solution {
|
||||
public:
|
||||
vector<vector<int>> levelOrder(TreeNode* root) {
|
||||
vector<vector<int>> result;
|
||||
std::queue<TreeNode*> myQueue;
|
||||
if(root==nullptr){
|
||||
return {};
|
||||
}
|
||||
// initial setup of the queue
|
||||
myQueue.push(root);
|
||||
while(!myQueue.empty()){
|
||||
int size = myQueue.size();
|
||||
vector<int> current_level;
|
||||
// assume every node at the next lever is in the queue, visit them one by one.
|
||||
for(int i=0;i<size;i++){
|
||||
TreeNode* current = myQueue.front();
|
||||
myQueue.pop();
|
||||
if(current!=nullptr){
|
||||
current_level.push_back(current->val);
|
||||
// before we get to the next level, push every node of the next level into the queue.
|
||||
if(current->left!=nullptr){
|
||||
myQueue.push(current->left);
|
||||
}
|
||||
if(current->right!=nullptr){
|
||||
myQueue.push(current->right);
|
||||
}
|
||||
}
|
||||
}
|
||||
result.push_back(current_level);
|
||||
}
|
||||
return result;
|
||||
}
|
||||
};
|
||||
Reference in New Issue
Block a user